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(PHP 3>= 3.0.16, PHP 4 )

imagecreatefromjpeg -- Create a new image from file or URL


resource imagecreatefromjpeg ( string filename)

imagecreatefromjpeg() returns an image identifier representing the image obtained from the given filename.

imagecreatefromjpeg() returns an empty string on failure. It also outputs an error message, which unfortunately displays as a broken link in a browser. To ease debugging the following example will produce an error JPEG:

Example 1. Example to handle an error during creation (courtesy vic at zymsys dot com )

function LoadJpeg ($imgname) {
    $im = @imagecreatefromjpeg ($imgname); /* Attempt to open */
    if (!$im) { /* See if it failed */
        $im  = imagecreate (150, 30); /* Create a blank image */
        $bgc = imagecolorallocate ($im, 255, 255, 255);
        $tc  = imagecolorallocate ($im, 0, 0, 0);
        imagefilledrectangle ($im, 0, 0, 150, 30, $bgc);
        /* Output an errmsg */
        imagestring ($im, 1, 5, 5, "Error loading $imgname", $tc);
    return $im;

Tip: You can use a URL as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename and Appendix I for a list of supported URL protocols.


Windows versions of PHP prior to PHP 4.3.0 do not support accessing remote files via this function, even if allow_url_fopen is enabled.

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